If a right triangular prism's height is 1 inch. The produced solid has the following surface area: = 2,930.05 in².
Right triangular prism describing:
A polyhedron with six vertices, nine edges, and five faces is a right triangular prism. Regular prisms have all of their triangles faces equilateral. The prism's rectangular faces will be congruent in this situation.
What is the method for determining a triangular prism's total surface area?
A triangular prism's total surface area is the sum of the areas of its three lateral faces (rectangles) as well as two bases (triangles). For something like the surface area of any prism, the most generic formula is:
According to the given data:
Given:
Hight = 1 inches
Base of the prism = 10 inches.
The Hight if the base = 82 inches.
Surface area = (Perimeter of the base × Length of the prism) + (2 × Base Area)
Surface area = 5(10× 10) + (0.5÷ 10 × 1) + 3(10× 82)
Surface area = 5(100) +0.05+ 3(810)
Surface area = 500 +0.05 + 2430
Surface area = 2,930.05 in²
The produced solid has a surface area of approximately = 2,930.05 in².
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