The equation of the line as it passes through the point (-6, 1) is
y = 3x/2 + 10
Slope is the same as gradient which is the ratio of change in y to change in x. That is,
gradient m = Δy / Δx
Given that the equation of the line passes through the point (-6, 1) and is perpendicular to the graph of 2x + 3y = -5
Let us first find the slope, 3y = -2x - 5
y = -2x/3 - 5/3
Slope m = -2/3
Let us use the formula Mm = -1
M = -1/m
M = -1 × -3 /2
M = 3/2
The equation of the line as it passes through the point (-6, 1) will be
M = (Y - Y1) / (X - X1)
3/2 = (y - 1) / (x + 6)
Cross multiply
2(y - 1) = 3(x + 6)
2y - 2 = 3x + 18
Collect the like time
2y = 3x + 18 + 2
2y = 3x + 20
y = 3x/2 + 10
Therefore, the equation of the line as it passes through the point (-6, 1) is y = 3x/2 + 10
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