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The height of a golf ball hit into the air is modeled by the equation \large h=-16t^2+48t, where \large hrepresents the height, if feet, and \large t represents the number of seconds that have passed since the ball was hit.

What is the height of the ball after 2 seconds?

a
80 feet

b
16 feet

c
64 feet

d
32 feet

Respuesta :

Kekekat99

Answer:

32 feet.

Step-by-step explanation:

If t is the time in seconds and the problem asks us what the height is after 2 seconds, then that would mean t = 2.

So, now we can substitute 2 for t and solve.

-16 × 2² + 48 ×2

-16 × 4 + 96

-64 + 96

= 32 ft.

Hope this helps!

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