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A ball is accidentally dropped from the top of a tall building. It took 3.0 secs for the ball to hit the ground. The acceleration of gravity is g = 10 m/sec². Find the initial height from which the ball was dropped.​

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beicker

Answer:

[tex]{ \rm{s = ut + \frac{1}{2} {at}^{2} }} \\ \\ { \rm{h = 0 + \frac{1}{2} \times 10 \times {3}^{2} }} \\ \\ { \tt{h = 5 \times 9}} \\ { \tt{h = 45 \: m}}[/tex]

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