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anne and nanny use a metal alloy that is 16% copper to make jewelry how many ounces of an alloy that is 10% copper must be mixed with an alloy that is 20% copper to form 55 ounces of the desired alloy

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By solving a system of equations we conclude that they need to use 22 ounces of the 10% alloy and 33 ounces of the 20% alloy.

How many ounces of each alloy should they use?

First, let's define the variables we will use to solve this problem:

  • x = ounces of the 10% alloy copper they need to use.
  • y = ounces of the 20% alloy copper they need to use.

We know that they want to get 55 ounces, then:

x + y = 55

And the concentration of these 55 ounces must be 16%, then we can write other equation:

0.1*x + 0.2*y = 0.16*55

Then we have a system of equations:

x + y = 55

0.1*x + 0.2*y = 0.16*55

Isolating x on the first equation we get:

x = 55 - y

Now we can replace that in the other equation so we get:

0.1*(55 - y) + 0.2*y = 0.16*55 = 8.8

Now we can solve this for y.

5.5 - 0.1*y + 0.2*y = 8.8

5.5 + 0.1*y = 8.8

y = (8.8 - 5.5)/0.1 = 33

Then the value of x is:

x = 55 - y = 55 - 33 = 22

We conclude that they need to use 22 ounces of the 10% alloy and 33 ounces of the 20% alloy.

If you want to learn more about systems of equations:

https://brainly.com/question/13729904

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