Simplify three eighths times the quantity 1 plus the square root of 49 end quantity squared minus the quantity four minus one end quantity cubed.

−3
−2
21
24

Respuesta :

The given expression:

(3/8)*( 1 + √49)^2 - (4 - 1)^3

Can be simplified to -3.

So we have the equality:

(3/8)*( 1 + √49)^2 - (4 - 1)^3 = -3

Which means that the first option is the correct one.

How to simplify the given expression?

Here we have the expression:

(3/8)*( 1 + √49)^2 - (4 - 1)^3

(I think is something like that)

And we want to simplify it, so first let's simplify the things inside the two parentheses.

The first one is:

1 + √49

We know that 7*7 = 49, then the square root of 49 is 7.

1 + √49 = 1 + 7 = 8

The other one is:

4 - 1 = 3

Replacing that in the expression we get:

(3/8)*( 1 + √49)^2 - (4 - 1)^3 = (3/8)*(8)^2 - (3)^3

Now we can solve the exponents:

8^2 = 8*8 = 64

3^3 = 3*3*3 = 27

Replacing that we get:

(3/8)*64 - 27 = 3*8 - 27 = 24 - 27 = -3

We conclude that the given expression:

(3/8)*( 1 + √49)^2 - (4 - 1)^3

Can be simplified to -3.

If you want to learn more about algebraic expressions:

https://brainly.com/question/4344214

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