According to the given function, we can throw it to the height of 6.6 m. So, yes we can throw it high enough to reach the ledge.
The given equation is quadratic. A quadratic equation is defined as an equation of a single variable with the highest power of 2. In general, the quadratic equation can be expressed as h(x)= [tex]ax^2- bx + c[/tex], where a, b and c are arbitrary constants. The solution for a quadratic equation is given by:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
The maximum of a quadratic equation is given by:
= [tex]c-\frac{b^2}{4a}[/tex]
The length to be covered by throwing=6 meters
It is given that the height of the grappling hook you throw is a function h(t) = -4.9t² + 10t + 1.5
Here a =4.9, b = 10 and c = 1.5
The maximum of a quadratic equation is given by:
[tex]c-\frac{b^2}{4a}[/tex]
[tex]1.5-\frac{10^2}{4*(-4.9)}[/tex]
6.6
A throw can be made to reach the wall since the height of wall is less than the maximum value that is 6.6 m.
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