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exactly 25.0 ml of an aqueous solution of strontium hydroxide required 32.0 ml of 0.200 m nitric acid to neutralize it. what is the concentration of the strontium hydroxide solution? give only your numerical answer and do not include the m. for example, 0.262 or 1.25.

Respuesta :

BinithaR

Ba(OH)2(aq) + 2HNO3(aq) ==> 2H2O(l) + Ba(NO3)2(aq)  ...  balanced equation

What is balanced equation?

A chemical equation that is balanced has the same number of each type of atom on both sides of the equation. Subscripts are a component of the chemical formulas for the reactants and products that show how many atoms of the previous element there are in each.

note the stoichiometry ...  2 mols HNO3 for each 1 mol Ba(OH)2

Now we can use dimensional analysis and the noted stoichiometry to solve the problem:

32.0 ml HNO3 x 1 L/1000 ml x 0.200 mol / L = 0.0064 mols HNO3 used

0.0064 mol HNO3 x 1 mol Ba(OH)2 / 2 mols HNO3 = 0.0032 mol Ba(OH)2 present

Concentration of Ba(OH)2 = mols/L = 0.0032 mols / 0.0250 L = 0.128 M

To learn more about balanced equation refer to:

https://brainly.com/question/26694427

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