a 13-ft ladder rests against a vertical wall. if the bottom of the ladder slides away at 1 ft/s, at what rate is the top of the ladder sliding down the wall when the bottom of the ladder is 5 ft from the wall? g

Respuesta :

ayune

The given situation can be solved using the differential equation and the top of the ladder slides downward at 0.417 ft/s.

Let:

x be  the distance from the bottom of the ladder to the base of the wall

y  be the distance from the top of the ladder to the bottom of the wall

When the ladder is still, apply the Pythagorean Theorem,

x² + y² = 13²

5² + y² = 13²

y² = 169 - 25 = 144

y = 12 ft

When the ladder slides, apply the differential equation:

x² + y² = 13²

2x . dx/dt + 2y . dy/dt = 0

Substitute x = 5, dx/dt = 1, y = 12

2 . 5 . 1 + 2 . 12 . dy/dt = 0

24 dy/dt = -10

dy/dt = -5/12 = - 0.417 ft/s

The minus sign indicates that the ladder is sliding downward.

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