Respuesta :
(a) The work done when the gas expands isothermally against a constant external pressure is 87.992 kJ
(b) The work that would be done if the same expansion occurred reversibly is 167.4 J
Given that the mass of methane m is = 4.5 gram = 0.0045 kg
Volume occupies [tex]V_{1}[/tex] = [tex]12.7dm^{3}[/tex]
And volume is increased by [tex]3.3dm^{3}[/tex]
So, the increased volume [tex]V_{2}[/tex] is
12.7 + 3.3 = 16 litres
Given temperature T is 310K
Pressure is given as 210 Torr = 26664.5 Pa
(a) Now, at the given pressure the work done is given by
W = P( [tex]V_{2}[/tex] - [tex]V_{1}[/tex])
W = 26664.5 (16 - 12.7)
W = 87992.85 J
W = 87.992 kJ
(b) At reversible process work done is given by
W = nRT㏑[tex]\frac{V2}{V1}[/tex]
We have the given mass = 4.5 gram
Molar mass of methane = 16
So number of moles is
n = Mass in gram / Molar Mass
n = 4.5 / 16
n = 0.28125
So, work done is
W = 0.28125 × 8.314 × nRT㏑[tex]\frac{16}{12.7}[/tex]
W = 167.4 J
Know more about Reverse expansion: -https://brainly.com/question/17997117
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