in the laboratory, a student adds 44.2 ml of water to 20.6 ml of a 0.652 m hydroiodic acid solution. what is the concentration of the diluted solution? assume the volumes are additive.

Respuesta :

The concentration of diluted solution is 0.2 M.

The concentration and volume are related by the formula - [tex] M_{1}[/tex] [tex] V_{1}[/tex] = [tex] M_{2}[/tex] [tex] V_{2}[/tex], where [tex] M_{1}[/tex] and [tex] M_{2}[/tex] are initial and final concentration. [tex] V_{1}[/tex] and [tex] V_{2}[/tex] are initial and final volumes.

Keep the values in relation to find the concentration of final diluted solution.

0.652 × 20.6 = [tex] M_{2}[/tex] × (44.2 + 20.6)

Performing addition on Right Hand Side

0.652 × 20.6 = [tex] M_{2}[/tex] × 64.8

Performing multiplication and division

[tex] M_{2}[/tex] = 13.43÷64.8

[tex] M_{2}[/tex] = 0.2 M

Thus, the diluted solution is 0.2 M.

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