Respuesta :
Based on the dissociation of each of the given salts, we can calculate that there are b. 51.5 g of chloride ions per liter of the solution.
Each mol of calcium chloride (CaCl₂) dissociates to give 2 moles of chloride ions. The number of moles of chloride ions that comes from calcium chloride is:
2 * 0.200 mol = 0.400 mol
Each mol of magnesium chloride (MgCl₂) dissociates to give 2 moles of chloride ions. The number of moles of chloride ions that comes from magnesium chloride is:
2 * 0.150 mol = 0.300 mol
Each mol of sodium chloride (NaCl) dissociates to give 1 mol of chloride ions. The number of moles of chloride ions that comes from sodium chloride is thus 0.750 mol
The total number of moles (n) of chloride ions in the solution is:
n = 0.400 mol + 0.300 mol + 0.750 mol
n = 1.450 mol
Now, we can use the molar mass of the chloride ion (M = 35.5 g/mol) to calculate the mass (m) of chloride ions in 1 liter of solution:
n = m/M ⇒ m = n*M
m = 1.450 mol * 35.5 g/mol
m = 51.475 g
You can learn more about dissociation here:
brainly.com/question/13363803
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