The heat released by metal and added to water is the same which is 1039.83 joule.
The equilibrium condition of the system depends on the heat released from both gold and water. The total heat received by the system will equal to total heat released by objects. It should follow
Q released = Q received
The heat can be defined by
Q = m . c . ΔT
where Q is heat, m is mass, c is the specific heat constant and ΔT is the change in temperature.
The given parameters are
m = 17.27 g = 0.01727 kf
T1 = 92 ⁰C
T2 = 25.1 ⁰C
c = 900 J/kg⁰C
By substituting the given parameters, we can calculate the heat
Q = m . c . ΔT
Q = 0.01727 . 900 . (92 - 25.1)
Q = 1039.83 joule
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