30, 32, 37, 54, 67, 38, 44 what are the lower and upper bounds to identify an unusual data point. (use up to the first decimal place for your calculation: example 14.2)

Respuesta :

The lower and upper bounds are 16.7 and 69.5 respectively.

So, the numbers are 30, 32, 37, 54, 67, 38, and 44.

In order to determine the lower bound and upper bound

Mean x' =Σ[tex]\frac{x}{n}[/tex] = 302/7 = 43.1429 = 43.1

Variance [tex]s^{2}[/tex] =Σ[tex]\frac{(x-x')^{2}}{n-1}[/tex] = 1048.86/(7-1) = 174.80952

Standard deviation = √174.80952 = 13.221555 = 13.2

Values that deviate more than two standard deviations from the mean are exceptional.

[tex]x -2s = 43.1 - 2*13.2 = 16.7[/tex] is the lower bound for uncommon values.

The upper bound that is exceptional is equal to

[tex]x + 2s = 43.1 + 2(13.2) = 69.5[/tex]

Therefore, 16.7 and 69.5 are the lower and upper bounds of given data

To learn more about Standard deviation click here:

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