The probability that the mean weight of the sample babies would differ from the population mean by less than 54 grams is 0.4339.
For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.
First, solve for the z-score using the formula below.
z-score = (x – μ) / σ
where x = individual data value = 3316 grams - 54 grams = 3262
μ = mean = 3316 grams
σ = standard deviation = 324 grams
z-score = (3262 - 3316) / 324
z-score = -54 / 324
z-score = -0.1667
Find the probability that corresponds to the z-score in the z-table. (see attached images)
z-score = -0.1667
Using interpolation of values,
probability = 0.4339
Learn more about probability here: brainly.com/question/26822684
#SPJ4
