Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given the coordinate points (6, 2) and (10, 4), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = 10-(-4)/2-6
m = 10+4/-4
m = 14/-4
=-3.5
Get the intercept;
Get the required equation by substituting m = and c= into the equation y = mx+c
y = -3.5x + 32
Answer:
[tex]y-2=\dfrac{1}{2}(x-6)[/tex]
Step-by-step explanation:
To find the equation of a line that passes through two given points, first find its slope by substituting the given points into the slope formula.
[tex]\boxed{\begin{minipage}{4.4cm}\underline{Slope Formula}\\\\Slope $(m)=\dfrac{y_2-y_1}{x_2-x_1}$\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ \\are two points on the line.\\\end{minipage}}[/tex]
Define the points:
Substitute the points into the slope formula:
[tex]\implies m=\dfrac{4-2}{10-6}=\dfrac{2}{4}=\dfrac{1}{2}[/tex]
Therefore, the slope of the line is ¹/₂.
[tex]\boxed{\begin{minipage}{5.8 cm}\underline{Point-slope form of a linear equation}\\\\$y-y_1=m(x-x_1)$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $(x_1,y_1)$ is a point on the line.\\\end{minipage}}[/tex]
To find the equation in point-slope form, substitute the found slope and one of the given points into the point-slope formula:
[tex]\implies y-2=\dfrac{1}{2}(x-6)[/tex]
