Solution
The question would like us to evaluate the following expression
[tex]|3-6\left|-(12\div6+1\right)^2[/tex]
- We should deal with the modulus and bracket separately.
- After that, we can then perform the subtraction operation on the results of the modulus and bracket.
- This is done below:
[tex]\begin{gathered} |3-6|=|-3\left|\right? \\ |-3\left|\right?=3\text{ \lparen Because the modulus always returns a positive number\rparen} \end{gathered}[/tex]
Also,
[tex]\begin{gathered} \lparen12\div6+1)^2 \\ By\text{ the rules of PEDMAS,} \\ Division\text{ comes before Addition, thus, we should perform the division operation first} \\ 12\div6=2 \\ \\ \lparen2+1)^2=3^2=9 \end{gathered}[/tex]
Thus, combining both results, we have:
[tex]\begin{gathered} 3-9 \\ =-6 \end{gathered}[/tex]
Final Answer
The answer is -6
