We have the arithmetic progression given by
[tex]a_n=17n-104[/tex]if n = 1 we have the first term, n = 2 the second one and, so on, to find the 32nd term we just do n = 32, therefore
[tex]\begin{gathered} a_{32}=17\cdot32-104 \\ \\ a_{32}=544-104 \\ \\ a_{32}=440 \end{gathered}[/tex]The 32nd term is 440.