contestada

There are 215.0 mol of an unknown gas stored at a temperature of 1110 K in a large, 395 L container. R=0.0821 L·atm/(mol·K) In atm, what is the approximate pressure of the gas?

Respuesta :

Answer:

To solve this problem we use the ideal gas equation:

[tex]P.V=n.R.T[/tex]

Where:

P is the pressure of the gas

V is the volume of the container (395 L)

n is the number of moles present (215 mol)

R is the ideal gas constant (0.0821 L.atm/mol.K)

T is the temperature of the gas (1110 K)

So to calculate the pressuere we have to use the equation and the data:

[tex]\begin{gathered} P=\frac{n.R.T}{V} \\ P=\frac{215mol\text{ . }0.0821\frac{L.atm}{mol.K}\text{ . }1110K}{395L} \\ P=\text{ 49.6 atm} \end{gathered}[/tex]

So the answer is 49.6 atm.

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