Answer:
Given equation is, x+3y=6
To determine whether each order pair is a solution of the equation
(3,1)
we have that, when x=3 we get y=1
Let us check this in the equation.
Put x=3, we get
[tex]3+3y=6[/tex][tex]\begin{gathered} 3y=6-3 \\ 3y=3 \end{gathered}[/tex][tex]y=1[/tex]
Hence (3,1) is the solution of the equation.
(6,0)
Put x=6, we get,
[tex]6+3y=6[/tex][tex]y=0[/tex]
Hence (6,0) is the solution of the equation.
(-2,2/3)
Put x=-2, we get,
[tex]-2+3y=6[/tex]
[tex]3y=6+2[/tex]
[tex]y=\frac{8}{3}[/tex]
Hence (-2,2/3) is not the solution of the equation.
