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A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 81 m long and 60 m wide. Find the area of the training field. Use the value 3.14 for n, and do not round your answer. Be sure to include the correct unit in your answer.

A training field is formed by joining a rectangle and two semicircles as shown below The rectangle is 81 m long and 60 m wide Find the area of the training fiel class=

Respuesta :

ANSWER:

EXPLANATION:

Given:

To find:

The area of the training field

We can see that the two semicircles will form a circle with a diameter(d) of 60 m, so the radius(r) of the circle will be;

r = d/2 = 60/2 = 30 m

Given pi as 3.14, we can go ahead and determine the area of the circle as seen below;

[tex]\begin{gathered} Area\text{ of the circle}=\pi r^2 \\ \\ =3.14*30^2 \\ \\ =3.14*900 \\ \\ =2826\text{ m}^2 \end{gathered}[/tex]

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