[tex](5-2i)(4+3i)[/tex]
At first, we multiply 5 by 4
[tex]5\times4=20[/tex]
Then multiply 5 by 3i
[tex]5\times3i=15i[/tex]
Then multiply -2i by 4
[tex]-2i\times4=-8i[/tex]
Then multiply -2i by 3i
[tex]-2i\times3i=-6i^2[/tex]
Since i^2 = -1, then we will multiply -6 by -1
[tex]-2i\times3i=-6i^2=-6\times-1=6[/tex]
Now, we will add the terms
[tex]20+15i-8i+6[/tex]
Then we will add the like terms
[tex]20+15i-8i+6=(20+6)+(15i-8i)=26+7i[/tex]
So the answer is b
