To answer this question, we will use the following formula for the equation of a line that passes through (x₁,y₁), and has slope m:
[tex]y-y_1=m(x-x_1)\text{.}[/tex]Substituting (x₁,y₁)=(-5,-3) and m=-3/5 in the above formula we get:
[tex]y-(-3)=-\frac{3}{5}(x-(-5))\text{.}[/tex]Simplifying the above equation we get:
[tex]\begin{gathered} y+3=-\frac{3}{5}(x+5), \\ y+3=-\frac{3}{5}x-\frac{3}{5}5, \\ y+3=-\frac{3}{5}x-3, \\ y+3-3=-\frac{3}{5}x-3-3, \\ y=-\frac{3}{5}x-6. \end{gathered}[/tex]Answer:
[tex]y=-\frac{3}{5}x-6\text{.}[/tex]