Respuesta :
Given:
The applied force is,
[tex]F=33\text{ N}[/tex]The mass of the object is,
[tex]m=7\text{ kg}[/tex]The constant velocity of the object is,
[tex]v=6.3\text{ m/s}[/tex]To find:
The coefficient of friction between the object and the surface
Explanation:
The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.
If the coefficient of friction between the object and the surface is
[tex]\mu[/tex]we can write the frictional force as,
[tex]f=\mu mg[/tex]For equilibrium condition,
[tex]\begin{gathered} \mu mg=F \\ \mu=\frac{F}{mg} \\ \mu=\frac{33}{7\times10} \\ \mu=0.47 \end{gathered}[/tex]Hence, the coefficient of friction between the object and the surface is 0.47.
