A car is negotiating a flat circular curve of radius 50 m with a speed of 20 m/swithout slipping. The maximum centripetal force (provided by static friction) is 1.2 x10^4N. What is the mass of the car?1) 0.50 x 10^3 kg2) 1.0 x 10^3 kg3) 1.5 x 10^3kg4) 2.0 x 10^3 kg

Respuesta :

We are given a car that is experiencing a centripetal force.

The formula for the force is given by:

[tex]F_c=\frac{mv^2}{r}[/tex]

Where "m" is the mass, "v" is the velocity and "r" is the radius. Now we solve for the mass, first by multiplying both sides by r:

[tex]rF_c=mv^2[/tex]

Now we divide by the velocity squared:

[tex]\frac{rF_c}{v^2}=m[/tex]

Now we replace the known values:

[tex]\frac{(50m)(1.2\times10^4N)}{(20\frac{m}{s})^2}=m[/tex]

Solving the operations:

[tex]1500kg=m[/tex]

Therefore, the mass is 1500 kg.