Respuesta :

Given data:

[tex]\begin{gathered} Q_1=5.0\times10^{-8}\text{ C} \\ Q_2=1.0\times10^{-7}\text{ C} \\ r=0.15\text{ m} \end{gathered}[/tex]

The electrostatic force is given as,

[tex]F=\frac{KQ_1Q_2}{r^2}[/tex]

Here, K is electrostatic force constant.

Substituting all known values,

[tex]\begin{gathered} F=\frac{9\times10^9\times5\times10^{-8}\times1\times10^{-7}^{}}{(0.15)^2} \\ =2\times10^{-3}\text{ N} \end{gathered}[/tex]

Therefore, the force between the charges is 2×10^(-3) N. Hence, option (d) is the correct choice.