Pythagorean theorem
[tex]\begin{gathered} a^2=b^2+c^2,\text{ where a is the hypotenuse} \\ a^2=(6.5)^2+(4.9)^2 \\ a^2=42.25+24.01 \\ a^2=66.26 \\ a=\sqrt[]{66.26}=8.1^{\prime} \end{gathered}[/tex]
(Type an integer or decimal rounded to the nearest tenth as needed.)
Integer = 8'
decimal rounded to the nearest tenth as needed = 8.1'
