In the diagram below, FG is parallel to CD. If the length of CD is the same as the length of FE, CE = 26, and FG = 11, find the length of FE. Figures are not necessarily drawn to scale. State your answer in simplest radical form, if necessary.

In the diagram below FG is parallel to CD If the length of CD is the same as the length of FE CE 26 and FG 11 find the length of FE Figures are not necessarily class=

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Answer:

The length of FE is √286 units.

Explanation:

Let the length of FE = x

Since FG is parallel to CD, then triangles EFG and ECD are similar triangles.

The ratio of the corresponding sides are:

[tex]\frac{FE}{CE}=\frac{FG}{CD}[/tex]

Substitute the given values from the diagram above:

[tex]\frac{x}{26}=\frac{11}{x}[/tex]

We then solve the equation for x.

[tex]\begin{gathered} \text{ Cross multiply} \\ x^2=26\times11 \\ \text{ Take the square root of both sides} \\ x=\sqrt{26\times11} \\ x=\sqrt{286} \\ \implies FE=\sqrt{286}\text{ units} \end{gathered}[/tex]

The length of FE is √286 units (in simplest radical form).

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