To solve this question we have to use the ideal gas law:
[tex]PV=nRT[/tex]
Where P is the pressure, V is the volume, n the number of moles, R the constant of ideal gases and T the temperature.
Solve the equation for T and replace for the given values. Remember that R has a value of 0.082atmL/molK:
[tex]\begin{gathered} T=\frac{PV}{nR} \\ T=\frac{536atm\cdot645L}{352mol\cdot\frac{0.082atmL}{molK}}=11977.54K \end{gathered}[/tex]
According to this, the temperature of the gas is 11977.54K.
