Michael wants to save $55,000.00 for a down payment on a home. How much will he need to invest in anaccount with 8.5% APR, compounding daily, in order to reach his goal in 3 years?

Respuesta :

Step 1. The information that we have is:

The final amount that Michael wants to save is:

[tex]A=55,000[/tex]

We will call that amount A.

The annual percentage rate of the investment, which we will label as r, is:

[tex]r=8.5[/tex]

We will need this annual percentage rate represented as a decimal number, therefore, we divide it by 100:

[tex]\begin{gathered} r=8.5/100 \\ r=0.085 \end{gathered}[/tex]

The time of the investment, t, is 3 years:

[tex]t=3[/tex]

And it is compounded daily, let n be the number of times of compounding in a year:

[tex]n=365[/tex]

Step 2. We need to find the initial amount of the investment, which will be called P or principal.

The formula we will use to find it is:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Step 3. Substituting the known values:

[tex]55,000=P(1+\frac{0.085}{365})^{(365)(3)}[/tex]

From this equation, we need to solve the operations and solve for P, the principal amount of the investment.

Step 4. Simplifying the equation:

[tex]55,000=P(1+0.0002328767)^{1095}[/tex]

Continue simplifying:

[tex]\begin{gathered} 55,000=P(1.0002328767)^{1,095} \\ 55,000=P(1.2904233) \end{gathered}[/tex]

Then, we solve for P:

[tex]\begin{gathered} \frac{55,000}{1.2904233}=P \\ 42,621.6726=P \end{gathered}[/tex]

Rounding to the nearest cent (2 decimal places) The amount that he needs to invest is $42,621.67

Answer: $42,621.67