which number below comes first when the numbers are listed from least to greatest? Explain. Then write the numbers in order from least to greatest 1/6, -3, the square root of 5, -9 / 2, 4.6 which number comes first when the numbers are listed from least to greatest?A. 1/6B.-3C.-9/2D.Square root of 5E. 4.6

Respuesta :

Answer:

The number that comes first when the numbers are listed from least to greatest is;

[tex]\frac{-9}{2}[/tex]

And, arranging the numbers from least to greatest will give;

[tex]\frac{-9}{2},-3,\frac{1}{6},\sqrt{5},4.6[/tex]

Explanation:

We want to arrange the number given below from least to greatest;

[tex]\frac{1}{6},-3,\frac{-9}{2},\sqrt{5},4.6[/tex]

From the list of numbers, let us simplify each of them to their approximate decimal.

[tex]\begin{gathered} \frac{1}{6}=0.1667 \\ -3 \\ \frac{-9}{2}=-4.5 \\ \sqrt{5}=2.236 \\ 4.6 \end{gathered}[/tex]

From the given number, the highest negative number will be the least number.

Because the higher a negative number the lower it becomes.

The highest negative is -4.5 followed by -3.

So, arranging from the least to the greatest we have;

[tex]-4.5,-3,0.1667,2.236,4.6[/tex]

Rewriting it in its initial form we have;

[tex]\frac{-9}{2},-3,\frac{1}{6},\sqrt{5},4.6[/tex]

Therefore, The number that comes first when the numbers are listed from least to greatest is;

[tex]\frac{-9}{2}[/tex]

And, arranging the numbers from least to greatest will give;

[tex]\frac{-9}{2},-3,\frac{1}{6},\sqrt{5},4.6[/tex]