The proof below may or may not be correct. If the proof is incorrect, determine the first step number that is not justified and the reason it is not justified.

The first step number that is not justified and the reason it is not justified:
From the attached image
[tex]<\text{ECF}\congStep 1: is said to be correct cause all the range are equivalent and parallel
Step 2: is said to be correct AECF is a parrelologram because it is a quadilateral with two opposite equal sides
Step 3: is correct
[tex]\begin{gathered} \Delta BEC\cong\Delta\text{ECF}\ldots\text{..} \\ \text{parallel lines cut by a transverse form congruent alternate interior angle.} \end{gathered}[/tex]Step 4: is correct
[tex]<\text{BEC}\congStep 5: is correct [tex]<\text{BEC}\congStep 6 : is not correct , because corresponding parts of the congruent triangle are not congruent.
Step 7: is correct , because its a rhombus.