We have a sample that is:
[tex]115,39,160,240,176[/tex]a) We can find the median by first sorting the sample:
[tex]39,115,160,176,240[/tex]The median is the value that has 50% of the values below its values.
In this case, this value is in the third place of the sorted sample and has a value of 160.
b) We have to find the mean.
We can calculate it as:
[tex]\begin{gathered} \bar{x}=\frac{1}{n}\sum_{n\mathop{=}1}^5x_i \\ \\ \bar{x}=\frac{1}{5}(115+39+160+240+176) \\ \\ \bar{x}=\frac{1}{5}(730) \\ \\ \bar{x}=146 \end{gathered}[/tex]c) We have to calculate the variance. To find its value we will use the mean value we have just calculated:
[tex]\begin{gathered} s^2=\frac{1}{n}\sum_{n\mathop{=}1}^5(x_i-\bar{x})^2 \\ \\ s^2=\frac{1}{5}[(115-146)^2+(39-146)^2+(160-146)^2+(240-146)^2+(176-146)^2] \\ \\ s^2=\frac{1}{5}[(-31)^2+(-107)^2+(14)^2+(94)^2+(30)^2] \\ \\ s^2=\frac{1}{5}(961+11449+196+8836+900) \\ \\ s^2=\frac{1}{5}(22342) \\ \\ s^2=4468.4 \end{gathered}[/tex]d) We have to calculate the standard deviation. As we have already calculated the variance, we can calculate it as:
[tex]\begin{gathered} s=\sqrt{s^2} \\ s=\sqrt{4468.4} \\ s\approx66.85 \end{gathered}[/tex]e) We now have to find the coefficient of variation:
[tex]CV=\frac{s}{\bar{x}}=\frac{66.85}{146}\approx0.457876\cdot100\%\approx46\%[/tex]Answer:
a) 160
b) 146
c) 4468.4
d) 66.85
e) 46%
