Solution:
Given:
The table of values is given:
From the table,
We see the data is a linear function. This is because a linear function has domain values at regular intervals.
Also, the linear equation can be formed as shown below, indicating it is a linear function.
Considering two points, (3,1) and (1,2)
where,
[tex]\begin{gathered} x_1=3 \\ y_1=1 \\ x_2=1 \\ y_2=2 \\ \\ \text{Then,} \\ \text{slope, m is given by;} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ \\ \text{Substituting the values into the formula above,} \\ m=\frac{2-1}{1-3} \\ m=\frac{1}{-2} \\ m=-\frac{1}{2} \end{gathered}[/tex]A linear equation is of the form;
[tex]\begin{gathered} y=mx+b \\ \text{where m is the slope} \\ b\text{ is the y-intercept} \\ \\ To\text{ get the value of the y-intercept, we use any given point} \\ U\sin g\text{ point (3,1)} \\ y=mx+b \\ 1=-\frac{1}{2}(3)+b \\ 1=-\frac{3}{2}+b \\ 1+\frac{3}{2}=b \\ 1+1.5=b \\ b=2.5 \\ \\ \\ \text{Thus, the linear equation is;} \\ y=-\frac{1}{2}x+2.5 \end{gathered}[/tex]From the above, has confirmed it is a linear function and not an exponential function, we can deduce that;
a) The function is not an exponential function.
b) The domain values (x-values) are at regular intervals
c) The range values (y-values) have a common difference of 1
Therefore, the correct answer is OPTION A
