For this question we know that we have a point (-3,-2) and we want to find an equation perpendicular to the line
y=2/3x-2.
Since both lines are perpendicular we need to satisfy this:
[tex]m_1\cdot m_2=-1[/tex]With m1= 2/3. If we solve for m2 we got:
[tex]m_2=\frac{-1}{m_1}=\frac{-1}{\frac{2}{3}}=-\frac{3}{2}[/tex]And then we can find the intercept for the new line using the point given with x=-3 and y=-2 and we got this:
[tex]-2=-\frac{3}{2}(-3)+b[/tex]And solving for b we got:
[tex]b=-\frac{9}{2}-2=-\frac{13}{2}[/tex]And then our final answer would be:
[tex]y=-\frac{3}{2}x-\frac{13}{2}[/tex]