Calculate the depth in the ocean at which thepressure is three times atmospheric pressure.Atmospheric pressure is 1.013 x 10^5 Pa. Theacceleration of gravity is 9.81 m/s^2and them/sdensity of sea water is 1025 kg/m^3Answer in units of m.

Respuesta :

In order to determine the depth in the ocean, use the following equation:

[tex]h=\frac{P-P_o}{\rho g}[/tex]

h: depth

P: pressure = 3*Po

Po: atmospheric pressure = 1.013*10^5Pa

g: gravitational acceleration constant = 9.8m/s^2

p: density of water = 1025 kg/m^3

Replace the previoua values into the formula for h and simplify:

[tex]\begin{gathered} h=\frac{3P_o-P_o}{\rho g}=\frac{2P_o}{\rho g} \\ h=\frac{2(1.013\cdot10^5Pa)}{(1025\frac{kg}{m^3})(9.8\frac{m}{s^2})}\approx20.17m \end{gathered}[/tex]

Hence, the depth in the ocean is approximately 20.17m