Solution
we are given the sequence
[tex]2,8,14,20,26,..[/tex]The first term = 2
Common difference = 6
The sequence is an arithmetic progression
The nth term is given as
[tex]\begin{gathered} a_n=a+(n-1)d \\ a=2 \\ d=6 \\ a_n=2+(n-1)(6) \\ a_n=2+6n-6 \\ a_n=6n-4 \end{gathered}[/tex]Therefore, the answer is
[tex]a_{n}=6n-4[/tex]