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If the area of a rectangular field is x2 – 3x + 4 units and the width is 2x – 3, then find the length of the rectangular field.x2- 3 x + 42 x − 3 unitsx2 - 3x + 4 units2x - 3 units3x + 4 units

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Solution

We are given the following

[tex]\begin{gathered} Area=x^2-3x+4 \\ \\ Width=2x-3 \\ \\ Length=? \end{gathered}[/tex]

Using the Area of a Rectangle we have

[tex]\begin{gathered} Area=lw \\ \\ l=\frac{A}{w} \\ \\ l=\frac{x^2-3x+4}{2x-3} \end{gathered}[/tex]

Therefore, the answer is

[tex]\frac{x^{2}-3x+4}{2x-3}units[/tex]

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