ANSWER:
[tex]\begin{gathered} (5x+3)\cdot(x+4) \\ x=-\frac{3}{5}\text{ and }x=-4 \end{gathered}[/tex]STEP-BY-STEP EXPLANATION:
We have the following function:
[tex]5x^2+23x+12[/tex]we factor and calculate the roots like this:
[tex]\begin{gathered} (5x+3)\cdot(x+4) \\ (5x+3)=0\rightarrow x=-\frac{3}{5} \\ (x+4)=0\rightarrow x=-4 \end{gathered}[/tex]Therefore the factored form would be
[tex](5x+3)\cdot(x+4)[/tex]And the roots of the functions are - 3/5 and -4
