Given:
• Ammeter reading, I = 1.0 A
,
• R1 = 2.0 Ω
,
• R2 = 4.0 Ω
,
• R3 = 5.0 Ω
Let's find the magnitude of the currents in I1 and I2.
Apply Kirchhoff's Current Law.
We have:
[tex]I_1+I_2+I_3=0[/tex]
From Kirchoff's junction rule:
[tex]I_1-I_2-I_3=1A[/tex]
Thus, we have:
[tex]\begin{gathered} \frac{1}{R_{eq}}=\frac{1}{2}+\frac{1}{4}+\frac{1}{5} \\ \\ \frac{1}{R_{eq}}=\frac{10+5+4}{20}=\frac{19}{20} \\ \\ R_{eq}=\frac{20}{19}=1.1\text{ ohms} \end{gathered}[/tex]
Apply Ohm's law to find the voltage in the circuit:
[tex]\begin{gathered} V=IR \\ \\ V=1.0*1.1 \\ \\ V=1.1\text{ V} \end{gathered}[/tex]
To find I1, apply Kirchoff's loop law:
[tex][/tex]
