2.0724moles
Given the balanced chemical reaction between Na2CO3 and CaCl2 expressed as:
[tex]Na_2CO_3+CaCl_2\rightarrow2NaCl+CaCO_3[/tex]Given the following parameters
Mass of CaCl₂ = 115g
Determine the moles of CaCl₂
[tex]\begin{gathered} moles\text{ of CaCl}_2=\frac{mass}{molar\text{ mass}} \\ moles\text{ of CaCl}_2=\frac{115}{110.98} \\ moles\text{ of CaCl}_2=1.0362moles \end{gathered}[/tex]According to stochiometry, 1 mole of CaCl2 prodcues 2 moles of NaCl. The moles of NaCl requred is given as:
[tex]\begin{gathered} moles\text{ of NaCl}=2\times1.0362 \\ moles\text{ of NaCl}=2.0724moles \end{gathered}[/tex]Therefore moles of NaCl made is 2.0724moles
