What is the volume of the cone rounded to the nearest tenth? The diagram is not drawn to scale. The height of the cone is 19 yd.A) 2646.3 yd^3B) 1462.4 yd^3C) 1039.0 yd^3D) 975.0 yd^3

What is the volume of the cone rounded to the nearest tenth The diagram is not drawn to scale The height of the cone is 19 ydA 26463 yd3B 14624 yd3C 10390 yd3D class=

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Answer:

To find the volume of the cone rounded to the nearest tenth

we have that,

Volume of the cone (V) is,

[tex]\frac{1}{3}\pi r^2h[/tex]

where r is the radius and h is the height of the cone.

Given that,

r=7 yd

h=19 yd

Substitute the values we get,

[tex]V=\frac{1}{3}\pi(7)^2\times19[/tex]

we get,

[tex]V=\frac{931}{3}\pi[/tex]

we know that pi is approximately equal to 3.14, Substitute the value we get,

[tex]V=\frac{931}{3}(3.14)[/tex]

we get,

[tex]V=974.446\approx975\text{ yd}^3[/tex]

Answer is: Option D:

[tex]\begin{equation*} 975\text{ yd}^3 \end{equation*}[/tex]