SOLUTION:
The given ratio is:
[tex]1:3[/tex]
• The given points are ,C(6, -5) and D (-3, 4).
Using the section formula, the coordinate of P is:
[tex]\begin{gathered} P=(\frac{1(-3)+3(6)}{1+3},\frac{1(4)+3(-5)}{1+3}) \\ P=(\frac{-3+18}{4},\frac{4-15}{4}) \\ P=(\frac{15}{4},\frac{-11}{4}) \end{gathered}[/tex]
Therefore the coordiantes of P
[tex]P=(\frac{15}{4},\frac{-11}{4})[/tex]
