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plant A produced 3 times as many panels as plant b. two percent of the panels from plant A and 5% of the panels from plant b were defective. how many panels did plant b produce if the two plants together produced 990 defective panels

Respuesta :

let x the number of panels that Plant A produced

y the number of panels that Plant B produced

then, we have

x = 3y

0.02x + 0.05y = 990

and solve the system:

[tex]\begin{gathered} 0.02(3y)+0.05y=990 \\ 0.06y+0.05y=990 \\ 0.11y=990 \\ \frac{0.11y}{0.11}=\frac{990}{0.11} \\ y=9000 \end{gathered}[/tex]

answer: plant b produced 9000 panels

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