Since the given equation is
[tex]y=\frac{3}{4}x^2[/tex]If x = 0, then
[tex]y=\frac{3}{4}(0)^2=0[/tex]Then x = 0 is correct because it gives the same value of y in the table
If x = 2
[tex]\begin{gathered} y=\frac{3}{4}(2)^2 \\ y=\frac{3}{4}(4) \\ y=3 \end{gathered}[/tex]Since the value of y in the table is 4
Then x = 2 is incorrect