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8. Three consecutive even numbers have a sum where one half of that sum is between 90 and 105. a. Write an inequality to find the three numbers. Let n represent the smallest even number. b. Solve the inequality. a. (n+(n+2)+(n+4) < −90 or −(n+(n+2)+(n+4)) > 105 b. n-62 or n > 68 a. 90 < 2(n + (n + 2) + (n + 4)) < 105 b. 13 ≤ n ≤ 15.5 a. 90 < ¹² (n + (n +2)+(n+ 4))

Respuesta :

Given:

Three consecutive even numbers have a sum where one half of that sum is between 90 and 105.

Required:

To write an inequality to find the three numbers and to solve the inequality.

Explanation:

(a)

Three consecutive even numbers have a sum where one half of that sum is between 90 and 105.

[tex]90<\frac{1}{2}(n+(n+2)+(n+4))<105[/tex]

(b)

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