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A special deck of cards has 4 blue cards, and 4 red cards. The blue cards are numbered 1, 2, 3, and 4. The red cards are numbered 1, 2, 3, and 4. The cards are well shuffled and you randomly draw one card.A = card drawn is blueB = card drawn is odd-numbereda) How many elements are there in the sample space? b) P(A) = c) P(B) =

A special deck of cards has 4 blue cards and 4 red cards The blue cards are numbered 1 2 3 and 4 The red cards are numbered 1 2 3 and 4 The cards are well shuff class=

Respuesta :

Answer

• a) 8

,

• b) 4/8

,

• c) 4/8

Explanation

Given

• Blue cards: 4, {B1, B2, B3, B4}

,

• Red cards: 4 {R1, R2, R3, R4}

,

• A = card drawn is blue

• B = card drawn is odd-numbered {B1, R1, B3, R3}

Procedure

• a) elements in the sample space

There are: S = {B1, B2, B3, B4, R1, R2, R3, R4}

Thus, the number of elements in the sample space is n(S) = 8.

• b) P(A)

Can be calculated as follows:

[tex]P(A)=\frac{n(A)}{n(S)}=\frac{4}{8}[/tex]

• c) P(B)

Can be calculated as follows:

[tex]P(B)=\frac{n(B)}{n(S)}=\frac{4}{8}[/tex]

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