The volume of a pyramid is given by the formula
[tex]V_{\text{pyramid}}=\frac{1}{3}\times base\text{ area}\times height[/tex]
Write out the given dimensions
[tex]\begin{gathered} \text{Volume}=80\operatorname{cm}^3 \\ \text{Height}=10\operatorname{cm} \\ \text{length}=6\operatorname{cm} \\ \text{width}=\text{unknown} \end{gathered}[/tex]
Since the base of the pyramid is a rectangle, the base area is
[tex]A_{\text{rectangle}}=\text{width }\times length[/tex]
Substituting the given dimensions to get the value of the width\
[tex]\begin{gathered} V_{\text{pyramid}}=\frac{1}{3}\times width\times length\times height \\ 80=\frac{1}{3}\times width\times6\operatorname{cm}\times10\operatorname{cm} \end{gathered}[/tex][tex]\begin{gathered} 80\operatorname{cm}=20\times width \\ \text{width}=\frac{80}{20} \\ \text{width}=4\operatorname{cm} \end{gathered}[/tex]
Hence, the width of the pyramid is 4cm
