Given the picture attached, we can use trigonometric functions to solve for x, as follows:
[tex]sin(x)=\frac{opposite}{hypothenuse}[/tex]
Replacing data in the formula:
[tex]\begin{gathered} sin(x)=\frac{30}{39} \\ \\ x=arcsin(\frac{30}{39}) \end{gathered}[/tex]
ANSWER
x = 50.28°
