The net of a cone is shown below. What is the surface area of the cone rounded to the nearest tenth of a square inch? Use π = 3.14.A. 125.6 in²B. 1,256.6 in²C. 175.8 in²D. 251.3 in²

ANSWER
[tex](C)175.8in^2[/tex]EXPLANATION
The surface area of a cone can be found using the formula:
[tex]A=\pi r^2+\pi rl[/tex]where l = slant height
r = radius
The diameter of the cone is given, but we can find the radius since the radius is half the diameter:
[tex]\begin{gathered} r=\frac{D}{2} \\ r=\frac{8}{2} \\ r=4\text{ units} \end{gathered}[/tex]From the figure, the slant height of the cone is 10 units.
Hence, its surface area is:
[tex]\begin{gathered} A=(\pi\cdot4^2)+(\pi\cdot4\cdot10) \\ A=50.24+125.6 \\ A\approx175.8in^2 \end{gathered}[/tex]The answer is option C.